How does the debugger statement behave with async functions?
async function fetchUserData() {
debugger;
const response = await fetch('/api/user');
const data = await response.json();
return data;
}
The debugger statement in async functions: 1) Pauses execution at the statement location before any async operations, 2) Allows inspection of the async function's context, 3) Can be used with async/await syntax effectively, 4) Enables debugging of promise-based code flow, 5) Helps track async execution paths, 6) Useful for debugging API calls and async operations, 7) Maintains proper async stack traces in DevTools, 8) Facilitates debugging of complex async workflows.