The output will be a `ReferenceError`. This code creates a named function expression where `g` is the function name and `f` is the variable to which the function is assigned. In a named function expression, the function name (in this case, `g`) is only accessible within the function's own scope, not in the outer scope where the `console.log` statement is trying to access it. Since `g` is not defined in the outer scope, attempting to call `g()` results in a ReferenceError. This demonstrates an important aspect of named function expressions: the function name provides an internal reference that's useful for recursion within the function or for more informative stack traces during debugging, but it doesn't create a binding in the surrounding scope. Only the variable name (`f` in this case) can be used to reference the function from outside.