Function Currying

function add(a, b) { return a + b; }
const add = (a) => (b) => a + b;
The expression `const add = (a) => (b) => a + b;` demonstrates a curried function. Instead of taking multiple arguments at once like `add(a, b)`, this curried version takes the first argument and returns a new function that takes the second argument. To use it, you would call it like `add(2)(3)` instead of `add(2, 3)`. The outer function captures the first argument in its closure, and the returned inner function uses that captured value along with its own argument to compute the final result.
function add(...args) { return args.reduce((a, b) => a + b); }
const add = (a, b) => { return { sum: a + b }; }